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e^{i\pi} + 1 = 0

e^{i x} = \cos x + i \sin x

\displaystyle \sum_{n} \frac{1}{n^s} = \prod_{p} {\frac{1}{1 - \frac{1}{p^s}}}

\displaystyle\int_{-\infty}^\infty e^{-x^2}dx = \sqrt{\pi}